X^2+63x-882=0

Solution for X^2+63x-882=0 equation:

X^2+63X-882=0

a = 1; b = 63; c = -882;
Δ = b2-4ac
Δ = 632-4·1·(-882)
Δ = 7497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7497}=\sqrt{441*17}=\sqrt{441}*\sqrt{17}=21\sqrt{17}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-21\sqrt{17}}{2*1}=\frac{-63-21\sqrt{17}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+21\sqrt{17}}{2*1}=\frac{-63+21\sqrt{17}}{2}
$